Integrand size = 27, antiderivative size = 32 \[ \int (a+a \cos (c+d x)) (A+B \cos (c+d x)) \sec (c+d x) \, dx=a (A+B) x+\frac {a A \text {arctanh}(\sin (c+d x))}{d}+\frac {a B \sin (c+d x)}{d} \]
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Time = 0.10 (sec) , antiderivative size = 32, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.148, Rules used = {3047, 3102, 2814, 3855} \[ \int (a+a \cos (c+d x)) (A+B \cos (c+d x)) \sec (c+d x) \, dx=\frac {a A \text {arctanh}(\sin (c+d x))}{d}+a x (A+B)+\frac {a B \sin (c+d x)}{d} \]
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Rule 2814
Rule 3047
Rule 3102
Rule 3855
Rubi steps \begin{align*} \text {integral}& = \int \left (a A+(a A+a B) \cos (c+d x)+a B \cos ^2(c+d x)\right ) \sec (c+d x) \, dx \\ & = \frac {a B \sin (c+d x)}{d}+\int (a A+a (A+B) \cos (c+d x)) \sec (c+d x) \, dx \\ & = a (A+B) x+\frac {a B \sin (c+d x)}{d}+(a A) \int \sec (c+d x) \, dx \\ & = a (A+B) x+\frac {a A \text {arctanh}(\sin (c+d x))}{d}+\frac {a B \sin (c+d x)}{d} \\ \end{align*}
Time = 0.02 (sec) , antiderivative size = 46, normalized size of antiderivative = 1.44 \[ \int (a+a \cos (c+d x)) (A+B \cos (c+d x)) \sec (c+d x) \, dx=a A x+a B x+\frac {a A \text {arctanh}(\sin (c+d x))}{d}+\frac {a B \cos (d x) \sin (c)}{d}+\frac {a B \cos (c) \sin (d x)}{d} \]
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Time = 1.48 (sec) , antiderivative size = 48, normalized size of antiderivative = 1.50
method | result | size |
derivativedivides | \(\frac {a A \left (d x +c \right )+B a \sin \left (d x +c \right )+a A \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )+B a \left (d x +c \right )}{d}\) | \(48\) |
default | \(\frac {a A \left (d x +c \right )+B a \sin \left (d x +c \right )+a A \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )+B a \left (d x +c \right )}{d}\) | \(48\) |
parallelrisch | \(\frac {\left (-A \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )+A \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )+B \sin \left (d x +c \right )+\left (A +B \right ) x d \right ) a}{d}\) | \(50\) |
parts | \(\frac {a A \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{d}+\frac {\left (a A +B a \right ) \left (d x +c \right )}{d}+\frac {a B \sin \left (d x +c \right )}{d}\) | \(50\) |
risch | \(a x A +a B x -\frac {i B a \,{\mathrm e}^{i \left (d x +c \right )}}{2 d}+\frac {i B a \,{\mathrm e}^{-i \left (d x +c \right )}}{2 d}+\frac {a A \ln \left ({\mathrm e}^{i \left (d x +c \right )}+i\right )}{d}-\frac {a A \ln \left ({\mathrm e}^{i \left (d x +c \right )}-i\right )}{d}\) | \(83\) |
norman | \(\frac {\left (a A +B a \right ) x +\left (a A +B a \right ) x \left (\tan ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+\left (2 a A +2 B a \right ) x \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+\frac {2 B a \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{d}+\frac {2 B a \left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d}}{\left (1+\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )^{2}}+\frac {a A \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )}{d}-\frac {a A \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )}{d}\) | \(141\) |
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Time = 0.34 (sec) , antiderivative size = 51, normalized size of antiderivative = 1.59 \[ \int (a+a \cos (c+d x)) (A+B \cos (c+d x)) \sec (c+d x) \, dx=\frac {2 \, {\left (A + B\right )} a d x + A a \log \left (\sin \left (d x + c\right ) + 1\right ) - A a \log \left (-\sin \left (d x + c\right ) + 1\right ) + 2 \, B a \sin \left (d x + c\right )}{2 \, d} \]
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\[ \int (a+a \cos (c+d x)) (A+B \cos (c+d x)) \sec (c+d x) \, dx=a \left (\int A \sec {\left (c + d x \right )}\, dx + \int A \cos {\left (c + d x \right )} \sec {\left (c + d x \right )}\, dx + \int B \cos {\left (c + d x \right )} \sec {\left (c + d x \right )}\, dx + \int B \cos ^{2}{\left (c + d x \right )} \sec {\left (c + d x \right )}\, dx\right ) \]
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Time = 0.21 (sec) , antiderivative size = 47, normalized size of antiderivative = 1.47 \[ \int (a+a \cos (c+d x)) (A+B \cos (c+d x)) \sec (c+d x) \, dx=\frac {{\left (d x + c\right )} A a + {\left (d x + c\right )} B a + A a \log \left (\sec \left (d x + c\right ) + \tan \left (d x + c\right )\right ) + B a \sin \left (d x + c\right )}{d} \]
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Leaf count of result is larger than twice the leaf count of optimal. 79 vs. \(2 (32) = 64\).
Time = 0.30 (sec) , antiderivative size = 79, normalized size of antiderivative = 2.47 \[ \int (a+a \cos (c+d x)) (A+B \cos (c+d x)) \sec (c+d x) \, dx=\frac {A a \log \left ({\left | \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 1 \right |}\right ) - A a \log \left ({\left | \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 1 \right |}\right ) + {\left (A a + B a\right )} {\left (d x + c\right )} + \frac {2 \, B a \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )}{\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 1}}{d} \]
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Time = 0.18 (sec) , antiderivative size = 100, normalized size of antiderivative = 3.12 \[ \int (a+a \cos (c+d x)) (A+B \cos (c+d x)) \sec (c+d x) \, dx=\frac {B\,a\,\sin \left (c+d\,x\right )}{d}+\frac {2\,A\,a\,\mathrm {atan}\left (\frac {\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )}{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}\right )}{d}+\frac {2\,A\,a\,\mathrm {atanh}\left (\frac {\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )}{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}\right )}{d}+\frac {2\,B\,a\,\mathrm {atan}\left (\frac {\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )}{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}\right )}{d} \]
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